I have that the pdf for a uniform distribution is given by $$f (x) = \frac {1} {b-a}$$ if $a \leq x \leq b $ and $0$ otherwise. I am trying to derive the cdf. From definition I have that the cdf is ...

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Here the density $f$ is the uniform density $f (x)$, which equals $1$ for $0<x<1$, and is zero otherwise. The integrand $f (x)f (z-x)$ will therefore have value either $1$ or $0$.

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Jul 21, 2023 · But the uniform distribution has a continuous density defined over a bounded interval, so physical intuition leads to the "obvious" conclusion without resorting to an explicit integration.

Mapping a PDF to a uniform distribution on (0, 1) (0, 1) Ask Question Asked 9 years, 7 months ago Modified 9 years, 7 months ago